.MCAD 304020000 1 74 93 0 .CMD PLOTFORMAT 0 0 1 1 1 0 0 1 1 0 0 1 1 1 0 0 1 1 0 1 0 0 1 1 NO-TRACE-STRING 0 2 1 0 1 1 NO-TRACE-STRING 0 3 2 0 1 1 NO-TRACE-STRING 0 4 3 0 1 1 NO-TRACE-STRING 0 1 4 0 1 1 NO-TRACE-STRING 0 2 5 0 1 1 NO-TRACE-STRING 0 3 6 0 1 1 NO-TRACE-STRING 0 4 0 0 1 1 NO-TRACE-STRING 0 1 1 0 1 1 NO-TRACE-STRING 0 2 2 0 1 1 NO-TRACE-STRING 0 3 3 0 1 1 NO-TRACE-STRING 0 4 4 0 1 1 NO-TRACE-STRING 0 1 5 0 1 1 NO-TRACE-STRING 0 2 6 0 1 1 NO-TRACE-STRING 0 3 0 0 1 1 NO-TRACE-STRING 0 4 1 0 1 1 NO-TRACE-STRING 0 1 1 21 15 0 0 3 .CMD FORMAT rd=d ct=10 im=i et=3 zt=15 pr=3 mass length time charge temperature tr=0 vm=0 .CMD SET ORIGIN 0 .CMD SET TOL 0.001000000000000 .CMD SET PRNCOLWIDTH 8 .CMD SET PRNPRECISION 4 .CMD PRINT_SETUP 1.200000 0.979167 1.200000 1.200000 0 .CMD HEADER_FOOTER 1 1 *empty* *empty* *empty* 0 1 *empty* *empty* *empty* .CMD HEADER_FOOTER_FONT fontID=14 family=Arial points=10 bold=0 italic=0 underline=0 colrid=-1 .CMD HEADER_FOOTER_FONT fontID=15 family=Arial points=10 bold=0 italic=0 underline=0 colrid=-1 .CMD DEFAULT_TEXT_PARPROPS 0 0 0 .CMD DEFINE_FONTSTYLE_NAME fontID=0 name=Variables .CMD DEFINE_FONTSTYLE_NAME fontID=1 name=Constants .CMD DEFINE_FONTSTYLE_NAME fontID=2 name=Text .CMD DEFINE_FONTSTYLE_NAME fontID=4 name=User^1 .CMD DEFINE_FONTSTYLE_NAME fontID=5 name=User^2 .CMD DEFINE_FONTSTYLE_NAME fontID=6 name=User^3 .CMD DEFINE_FONTSTYLE_NAME fontID=7 name=User^4 .CMD DEFINE_FONTSTYLE_NAME fontID=8 name=User^5 .CMD DEFINE_FONTSTYLE_NAME fontID=9 name=User^6 .CMD DEFINE_FONTSTYLE_NAME fontID=10 name=User^7 .CMD DEFINE_FONTSTYLE fontID=0 family=Times^New^Roman points=10 bold=0 italic=0 underline=0 colrid=-1 .CMD DEFINE_FONTSTYLE fontID=1 family=Times^New^Roman points=10 bold=0 italic=0 underline=0 colrid=-1 .CMD DEFINE_FONTSTYLE fontID=2 family=Arial points=10 bold=0 italic=0 underline=0 colrid=-1 .CMD DEFINE_FONTSTYLE fontID=4 family=Arial points=10 bold=0 italic=0 underline=0 colrid=-1 .CMD DEFINE_FONTSTYLE fontID=5 family=Courier^New points=10 bold=0 italic=0 underline=0 colrid=-1 .CMD DEFINE_FONTSTYLE fontID=6 family=System points=10 bold=0 italic=0 underline=0 colrid=-1 .CMD DEFINE_FONTSTYLE fontID=7 family=Script points=10 bold=0 italic=0 underline=0 colrid=-1 .CMD DEFINE_FONTSTYLE fontID=8 family=Roman points=10 bold=0 italic=0 underline=0 colrid=-1 .CMD DEFINE_FONTSTYLE fontID=9 family=Modern points=10 bold=0 italic=0 underline=0 colrid=-1 .CMD DEFINE_FONTSTYLE fontID=10 family=Times^New^Roman points=10 bold=0 italic=0 underline=0 colrid=-1 .CMD UNITS U=1 .CMD DIMENSIONS_ANALYSIS 0 0 .CMD COLORTAB_ENTRY 0 0 0 .CMD COLORTAB_ENTRY 128 0 0 .CMD COLORTAB_ENTRY 0 128 0 .CMD COLORTAB_ENTRY 128 128 0 .CMD COLORTAB_ENTRY 0 0 128 .CMD COLORTAB_ENTRY 128 0 128 .CMD COLORTAB_ENTRY 0 128 128 .CMD COLORTAB_ENTRY 128 128 128 .CMD COLORTAB_ENTRY 192 192 192 .CMD COLORTAB_ENTRY 255 0 0 .CMD COLORTAB_ENTRY 0 255 0 .CMD COLORTAB_ENTRY 255 255 0 .CMD COLORTAB_ENTRY 0 0 255 .CMD COLORTAB_ENTRY 255 0 255 .CMD COLORTAB_ENTRY 0 255 255 .CMD COLORTAB_ENTRY 255 255 255 .TXT 5 7 1 0 0 Cg a67.000000,67.000000,25 {\rtf\ansi \deff0{\colortbl;\red0\green0\blue128;}{\fonttbl{\f0 \fcharset0\fnil Arial;}}\plain\cf1\fs20 \pard {\fs32 MathCad Session in MAT200}} .EQN 4 30 12 0 0 {0:a}NAME:3 .TXT 1 -30 8 0 0 Cg a67.000000,67.000000,60 {\rtf\ansi \deff0{\colortbl;\red0\green0\blue128;}{\fonttbl{\f0 \fcharset0\fnil Arial;}}\plain\cf1\fs20 \pard Defining a constant\par and evaluating expressions\par containing it} .EQN 2 30 13 0 0 {0:a}NAME+1={0}?_n_u_l_l_ .EQN 3 0 14 0 0 ({0:a}NAME)^(2)={0}?_n_u_l_l_ .TXT 4 -30 11 0 0 Cg a67.000000,67.000000,54 {\rtf\ansi \deff0{\colortbl;\red0\green0\blue128;}{\fonttbl{\f0 \fcharset0\fnil Arial;}}\plain\cf1\fs20 \pard Create formulas with the constant a\par and the variable x} .EQN 1 30 18 0 0 (({0:a}NAME)^(3)+({0:a}NAME)^(2))/(({0:a}NAME)^(2)+3)={0}?_n_u_l_l_ .EQN 6 0 16 0 0 (({0:x}NAME)^(2)+{0:a}NAME)/(({0:x}NAME)^(2)+3){63}1 .TXT 5 -30 19 0 0 Cg a67.000000,67.000000,19 {\rtf\ansi \deff0{\colortbl;\red0\green0\blue128;}{\fonttbl{\f0 \fcharset0\fnil Arial;}}\plain\cf1\fs20 \pard Define functions...} .EQN 1 29 20 0 0 {0:f}NAME({0:x}NAME):({0:x}NAME)^(2)-2 .EQN 3 0 21 0 0 {0:g}NAME({0:x}NAME):\({0:ln}NAME({0:x}NAME)) .TXT 4 -24 22 0 0 Cg a62.000000,62.000000,27 {\rtf\ansi \deff0{\colortbl;\red0\green0\blue128;}{\fonttbl{\f0 \fcharset0\fnil Arial;}}\plain\cf1\fs20 \pard ... and evaluating them ...} .EQN 0 24 23 0 0 {0:f}NAME(2)={0}?_n_u_l_l_ .EQN 3 0 25 0 0 {0:g}NAME(7)={0}?_n_u_l_l_ .TXT 5 -29 26 0 0 Cg a67.000000,67.000000,25 {\rtf\ansi \deff0{\colortbl;\red0\green0\blue128;}{\fonttbl{\f0 \fcharset0\fnil Arial;}}\plain\cf1\fs20 \pard Defining a range variable} .EQN 0 28 27 0 0 {0:t}NAME:0.1,0.2;2 .TXT 4 -28 28 0 0 Cg a67.000000,67.000000,6 {\rtf\ansi \deff0{\colortbl;\red0\green0\blue128;}{\fonttbl{\f0 \fcharset0\fnil Arial;}}\plain\cf1\fs20 \pard Tables} .EQN 0 22 29 0 0 {0:t}NAME= .EQN 0 4 30 0 0 {0:f}NAME({0:t}NAME)= .EQN 0 6 31 0 0 {0:g}NAME({0:t}NAME)= .TXT 52 -25 32 0 0 Cg a60.000000,60.000000,39 {\rtf\ansi \deff0{\colortbl;\red0\green0\blue128;}{\fonttbl{\f0 \fcharset0\fnil Arial;}}\plain\cf1\fs20 \pard and graphing, using the \par range variable} .EQN 1 11 34 0 0 &&(_n_u_l_l_&_n_u_l_l_)&{0:f}NAME({0:t}NAME),{0:g}NAME({0:t}NAME)@2&0&(_n_u_l_l_&_n_u_l_l_)&{0:t}NAME 0 0 1 1 1 0 0 1 1 0 0 1 1 1 0 0 1 1 0 1 0 0 2 2 NO-TRACE-STRING 0 1 1 0 2 2 NO-TRACE-STRING 0 3 2 0 1 1 NO-TRACE-STRING 0 4 3 0 1 1 NO-TRACE-STRING 0 1 4 0 1 1 NO-TRACE-STRING 0 2 5 0 1 1 NO-TRACE-STRING 0 3 6 0 1 1 NO-TRACE-STRING 0 4 0 0 1 1 NO-TRACE-STRING 0 1 1 0 1 1 NO-TRACE-STRING 0 2 2 0 1 1 NO-TRACE-STRING 0 3 3 0 1 1 NO-TRACE-STRING 0 4 4 0 1 1 NO-TRACE-STRING 0 1 5 0 1 1 NO-TRACE-STRING 0 2 6 0 1 1 NO-TRACE-STRING 0 3 0 0 1 1 NO-TRACE-STRING 0 4 1 0 1 1 NO-TRACE-STRING 0 1 2 36 38 10 0 3 .TXT 49 -10 35 0 0 Cg a59.000000,59.000000,47 {\rtf\ansi \deff0{\colortbl;\red0\green0\blue128;}{\fonttbl{\f0 \fcharset0\fnil Arial;}}\plain\cf1\fs20 \pard How the accuracy depends \par on the range variable} .EQN 0 24 39 0 0 {0:t}NAME:0.1,0.5;2 .EQN 5 -13 38 0 0 1&-2&(_n_u_l_l_&_n_u_l_l_)&{0:f}NAME({0:t}NAME),{0:g}NAME({0:t}NAME)@2&0&(_n_u_l_l_&_n_u_l_l_)&{0:t}NAME 0 0 1 1 1 0 0 1 1 0 0 1 1 1 0 0 1 1 0 1 0 0 2 2 NO-TRACE-STRING 0 1 1 0 2 2 NO-TRACE-STRING 0 3 2 0 1 1 NO-TRACE-STRING 0 4 3 0 1 1 NO-TRACE-STRING 0 1 4 0 1 1 NO-TRACE-STRING 0 2 5 0 1 1 NO-TRACE-STRING 0 3 6 0 1 1 NO-TRACE-STRING 0 4 0 0 1 1 NO-TRACE-STRING 0 1 1 0 1 1 NO-TRACE-STRING 0 2 2 0 1 1 NO-TRACE-STRING 0 3 3 0 1 1 NO-TRACE-STRING 0 4 4 0 1 1 NO-TRACE-STRING 0 1 5 0 1 1 NO-TRACE-STRING 0 2 6 0 1 1 NO-TRACE-STRING 0 3 0 0 1 1 NO-TRACE-STRING 0 4 1 0 1 1 NO-TRACE-STRING 0 1 2 34 24 10 0 3 .TXT 36 -14 40 0 0 Cg a62.000000,62.000000,58 {\rtf\ansi \deff0{\colortbl;\red0\green0\blue128;}{\fonttbl{\f0 \fcharset0\fnil Arial;}}\plain\cf1\fs20 \pard {\fs28 Derivatives} with \par variables, constants,\par and range variables} .EQN 0 19 41 0 0 {0:x}NAME"{0:f}NAME({0:x}NAME){63}2*{0:x}NAME .EQN 0 19 42 0 0 {0:a}NAME"{0:f}NAME({0:a}NAME)={0}?_n_u_l_l_ .TXT 0 10 44 0 0 Cg a14.000000,14.000000,28 {\rtf\ansi \deff0{\colortbl;\red0\green0\blue128;}{\fonttbl{\f0 \fcharset0\fnil Arial;}}\plain\cf1\fs20 \pard this latter\par stands for\par f'(a)} .TXT 5 -30 45 0 0 Cg a44.000000,44.000000,24 {\rtf\ansi \deff0{\colortbl;\red0\green0\blue128;}{\fonttbl{\f0 \fcharset0\fnil Arial;}}\plain\cf1\fs20 \pard symbolic differentiation} .EQN 6 1 51 0 0 {0:t}NAME"{0:f}NAME({0:t}NAME)= .TXT 23 -18 52 0 0 Cg a61.000000,61.000000,51 {\rtf\ansi \deff0{\colortbl;\red0\green0\blue128;}{\fonttbl{\f0 \fcharset0\fnil Arial;}}\plain\cf1\fs20 \pard Next we define h to be the derivative function of g} .EQN 4 15 48 0 0 {0:h}NAME({0:x}NAME):{0:x}NAME"{0:g}NAME({0:x}NAME) .EQN 0 18 49 0 0 {0:h}NAME(1.1)={0}?_n_u_l_l_ .EQN 0 15 57 0 0 {0:h}NAME(3)={0}?_n_u_l_l_ .EQN 4 -15 53 0 0 {0:h}NAME(1.5)={0}?_n_u_l_l_ .TXT 5 -33 54 0 0 Cg a61.000000,61.000000,61 {\rtf\ansi \deff0{\colortbl;\red0\green0\blue128;}{\fonttbl{\f0 \fcharset0\fnil Arial;}}\plain\cf1\fs20 \pard We graph g and its derivative h\par in the same coordinate system} .EQN 0 31 55 0 0 {0:t}NAME:1.1,1.2;3 .EQN 6 -14 60 0 0 &&(_n_u_l_l_&_n_u_l_l_)&{0:g}NAME({0:t}NAME),{0:h}NAME({0:t}NAME)@3&1.1&(_n_u_l_l_&_n_u_l_l_)&{0:t}NAME 0 0 1 1 1 0 0 1 1 0 0 1 1 1 0 0 1 1 0 1 0 0 2 2 NO-TRACE-STRING 0 1 1 0 2 2 NO-TRACE-STRING 0 3 2 0 1 1 NO-TRACE-STRING 0 4 3 0 1 1 NO-TRACE-STRING 0 1 4 0 1 1 NO-TRACE-STRING 0 2 5 0 1 1 NO-TRACE-STRING 0 3 6 0 1 1 NO-TRACE-STRING 0 4 0 0 1 1 NO-TRACE-STRING 0 1 1 0 1 1 NO-TRACE-STRING 0 2 2 0 1 1 NO-TRACE-STRING 0 3 3 0 1 1 NO-TRACE-STRING 0 4 4 0 1 1 NO-TRACE-STRING 0 1 5 0 1 1 NO-TRACE-STRING 0 2 6 0 1 1 NO-TRACE-STRING 0 3 0 0 1 1 NO-TRACE-STRING 0 4 1 0 1 1 NO-TRACE-STRING 0 1 1 31 34 10 0 3 .EQN 1 -14 58 0 0 {0:t}NAME= .EQN 0 6 59 0 0 {0:h}NAME({0:t}NAME)= .TXT 47 9 61 0 0 Cg a43.000000,43.000000,78 {\rtf\ansi \deff0{\colortbl;\red0\green0\blue128;}{\fonttbl{\f0 \fcharset0\fnil Arial;}}\plain\cf1\fs20 \pard what is the formula for h(x)=g'(x)? We use again the\par symbolic evaluation arrow} .EQN 7 0 65 0 0 {0:x}NAME"{0:g}NAME({0:x}NAME){63}(1)/((2*(\({0:ln}NAME({0:x}NAME))*{0:x}NAME))) .TXT 7 0 66 0 0 Cg a43.000000,43.000000,35 {\rtf\ansi \deff0{\colortbl;\red0\green0\blue128;}{\fonttbl{\f0 \fcharset0\fnil Arial;}}\plain\cf1\fs20 \pard What is the second derivative of g?} .EQN 6 0 67 0 0 ((2,{0:x}NAME,{0:g}NAME({0:x}NAME)){62}){63}(-1)/((4*(({0:ln}NAME({0:x}NAME))^(((3)/(2)))*({0:x}NAME)^(2))))-(1)/((2*(\({0:ln}NAME({0:x}NAME))*({0:x}NAME)^(2)))) .TXT 9 0 70 0 0 Cg a43.000000,43.000000,17 {\rtf\ansi \deff0{\colortbl;\red0\green0\blue128;}{\fonttbl{\f0 \fcharset0\fnil Arial;}}\plain\cf1\fs20 \pard Third derivative?} .EQN 5 -8 72 0 0 ((3,{0:x}NAME,{0:g}NAME({0:x}NAME)){62}){63}(3)/((8*(({0:ln}NAME({0:x}NAME))^(((5)/(2)))*({0:x}NAME)^(3))))+(3)/((4*(({0:ln}NAME({0:x}NAME))^(((3)/(2)))*({0:x}NAME)^(3))))+(1)/((\({0:ln}NAME({0:x}NAME))*({0:x}NAME)^(3))) .TXT 12 -12 73 0 0 Cg a63.000000,63.000000,28 {\rtf\ansi \deff0{\colortbl;\red0\green0\blue128;}{\fonttbl{\f0 \fcharset0\fnil Arial;}}\plain\cf1\fs20 \pard {\fs28 Integration:\par } Antiderivatives} .EQN 0 15 74 0 0 (({0:x}NAME,{0:f}NAME({0:x}NAME)){67}){63}(1)/(3)*({0:x}NAME)^(3)-2*{0:x}NAME .EQN 7 0 75 0 0 (({0:x}NAME,{0:h}NAME({0:x}NAME)){67}){63}(({0:x}NAME,{0:h}NAME({0:x}NAME)){67}) .TXT 1 25 80 0 0 Cg a23.000000,23.000000,44 {\rtf\ansi \deff0{\colortbl;\red0\green0\blue128;}{\fonttbl{\f0 \fcharset0\fnil Arial;}}\plain\cf1\fs20 \pard doesn't work like this, \par but try the next ...} .EQN 7 -25 76 0 0 (({0:x}NAME,(1)/(2*\({0:ln}NAME({0:x}NAME))*{0:x}NAME)){67}){63}\({0:ln}NAME({0:x}NAME)) .EQN 8 0 79 0 0 (({0:x}NAME,{0:x}NAME*({0:e}NAME)^({0:x}NAME)){67}){63}{0:x}NAME*{0:exp}NAME({0:x}NAME)-{0:exp}NAME({0:x}NAME) .EQN 7 0 83 0 0 (({0:x}NAME,({0:x}NAME)^(2)*({0:e}NAME)^({0:x}NAME)){67}){63}({0:x}NAME)^(2)*{0:exp}NAME({0:x}NAME)-2*{0:x}NAME*{0:exp}NAME({0:x}NAME)+2*{0:exp}NAME({0:x}NAME) .EQN 7 0 82 0 0 (({0:x}NAME,{0:ln}NAME({0:x}NAME)){67}){63}{0:x}NAME*{0:ln}NAME({0:x}NAME)-{0:x}NAME .TXT 11 -16 84 0 0 Cg a64.000000,64.000000,18 {\rtf\ansi \deff0{\colortbl;\red0\green0\blue128;}{\fonttbl{\f0 \fcharset0\fnil Arial;}}\plain\cf1\fs20 \pard What about {\fs28 Limits}?} .EQN 0 19 87 0 0 ((3,{0:x}NAME,({0:x}NAME-3)/({0:x}NAME+2)){68}){63}0 .EQN 7 0 91 0 0 ((-2,{0:x}NAME,({0:x}NAME-3)/({0:x}NAME+2)){68}){63}{0:undefined}NAME .EQN 8 0 93 0 0 ((4,{0:x}NAME,(\({0:x}NAME)-2)/({0:x}NAME-4)){68}){63}(1)/(4)