.MCAD 304020000 1 73 86 0
.CMD FORMAT  rd=d ct=10 im=i et=3 zt=15 pr=3 mass length time charge temperature tr=0 vm=0
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.CMD SET TOL 0.001000000000000
.CMD SET PRNCOLWIDTH 8
.CMD SET PRNPRECISION 4
.CMD PRINT_SETUP 1.200000 0.989583 1.200000 1.200000 0
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.TXT 5 12 41 0 0
Cg a61.875000,61.875000,21
{\rtf\ansi \deff0{\colortbl;\red0\green0\blue128;}{\fonttbl{\f0
\fcharset0\fswiss Arial;}}\plain\cf1\fs28 \pard Iterative Derivatives}
.EQN 2 42 42 0 0
{0:x}NAME:-2,-1.97;4
.TXT 6 -50 43 0 0
Cg a69.875000,69.875000,17
{\rtf\ansi \deff0{\colortbl;\red0\green0\blue128;}{\fonttbl{\f0
\fcharset0\fswiss Arial;}}\plain\cf1\fs28 \pard Take the function}
.EQN 0 19 45 0 1
{0:f}NAME({0:x}NAME):({0:x}NAME)^(3)-2*({0:x}NAME)^(2)-3*{0:x}NAME-4
.TXT 5 -19 46 0 0
Cg a69.875000,69.875000,69
{\rtf\ansi \deff0{\colortbl;\red0\green0\blue128;}{\fonttbl{\f0
\fcharset0\fswiss Arial;}}\plain\cf1\fs28 \pard and compute iterative 
derivatives f'(x), f''(x),  ... and graph them.}
.TXT 6 0 52 0 0
Cg a69.875000,69.875000,26
{\rtf\ansi \deff0{\colortbl;\red0\green0\blue128;}{\fonttbl{\f0
\fcharset0\fswiss Arial;}}\plain\cf1\fs28 \pard the derivative is 
called g}
.EQN 0 27 53 0 0
{0:g}NAME({0:x}NAME):{0:x}NAME"{0:f}NAME({0:x}NAME)
.EQN 9 -9 67 0 0
{0:x}NAME"{0:f}NAME({0:x}NAME){63}3*({0:x}NAME)^(2)-4*{0:x}NAME-3
.TXT 11 -18 62 0 0
Cg a69.875000,69.875000,34
{\rtf\ansi \deff0{\colortbl;\red0\green0\blue128;}{\fonttbl{\f0
\fcharset0\fswiss Arial;}}\plain\cf1\fs28 \pard let's call the second 
derivative h}
.EQN 0 37 64 0 0
{0:h}NAME({0:x}NAME):((2,{0:x}NAME,{0:f}NAME({0:x}NAME)){62})
.EQN 6 -19 77 0 0
((2,{0:x}NAME,{0:f}NAME({0:x}NAME)){62}){63}6*{0:x}NAME-4
.TXT 8 -18 70 0 0
Cg a69.875000,69.875000,30
{\rtf\ansi \deff0{\colortbl;\red0\green0\blue128;}{\fonttbl{\f0
\fcharset0\fswiss Arial;}}\plain\cf1\fs28 \pard ...a dn the third 
derivative k}
.EQN 2 37 71 0 0
{0:k}NAME({0:x}NAME):((3,{0:x}NAME,{0:f}NAME({0:x}NAME)){62})
.EQN 9 -18 76 0 0
((3,{0:x}NAME,{0:f}NAME({0:x}NAME)){62}){63}6
.TXT 14 -19 75 0 0
Cg a69.875000,69.875000,39
{\rtf\ansi \deff0{\colortbl;\red0\green0\blue128;}{\fonttbl{\f0
\fcharset0\fswiss Arial;}}\plain\cf1\fs28 \pard here is the graph of 
all four functions}
.EQN 3 -1 73 0 0
6&-10&(_n_u_l_l_&_n_u_l_l_)&{0:f}NAME({0:x}NAME),{0:g}NAME({0:x}NAME),{0:h}NAME({0:x}NAME),{0:k}NAME({0:x}NAME)@4&-2&(_n_u_l_l_&_n_u_l_l_)&{0:x}NAME
0 0 1 1 1 0 0 1 1 
0 0 1 1 1 0 0 1 1 
0 1 0 0 2 2 NO-TRACE-STRING
0 1 1 0 2 2 NO-TRACE-STRING
0 2 6 0 3 3 NO-TRACE-STRING
0 4 3 0 2 2 NO-TRACE-STRING
0 1 4 0 2 2 NO-TRACE-STRING
0 2 5 0 1 1 NO-TRACE-STRING
0 3 6 0 1 1 NO-TRACE-STRING
0 4 0 0 1 1 NO-TRACE-STRING
0 1 1 0 1 1 NO-TRACE-STRING
0 2 2 0 1 1 NO-TRACE-STRING
0 3 3 0 1 1 NO-TRACE-STRING
0 4 4 0 1 1 NO-TRACE-STRING
0 1 5 0 1 1 NO-TRACE-STRING
0 2 6 0 1 1 NO-TRACE-STRING
0 3 0 0 1 1 NO-TRACE-STRING
0 4 1 0 1 1 NO-TRACE-STRING
0 1 2 58 48 14 0 3 
.TXT 61 2 78 0 0
Cg a68.875000,68.875000,52
{\rtf\ansi \deff0{\colortbl;\red0\green0\blue128;}{\fonttbl{\f0
\fcharset0\fswiss Arial;}}\plain\cf1\fs28 \pard 
____________________________________________________}
.TXT 6 0 79 0 0
Cg a68.875000,68.875000,39
{\rtf\ansi \deff0{\colortbl;\red0\green0\blue128;}{\fonttbl{\f0
\fcharset0\fswiss Arial;}}\plain\cf1\fs28 \pard Try also the following 
functions for f:}
.EQN 5 0 82 0 0
{0:f}NAME({0:x}NAME):{0:ln}NAME({0:x}NAME)
.EQN 7 0 86 0 0
{0:f}NAME({0:x}NAME):({0:ln}NAME({0:x}NAME)+{0:x}NAME)/({0:exp}NAME({0:x}NAME))